Linux. find broadcast address of a given network interface

It's grotesque how in 2019 we still have to rely on primitive, ambiguous tools like grep and awk to extract information from a linux command

This is what I could came up to "find broadcast address of a given network interface":

ip a s dev docker0 | grep "inet.*brd" | awk '{print $4}'


To subtract 1 from IP (see here ):

cat checkip.ksh
echo "Enter ip:"
read IP_val
awk -F"/" -vvalip="$IP_val" '{if($NF==valip){split($1, A,".");A[4]-=1;VAL=A[1] OFS A[2] OFS A[3] OFS A[4]}} END{print VAL}' OFS="." ip_list

It's a mad world.

The broadcast address is always (?) the highest IP in the subnet range:

Network: 172.25.1.64/26
Broadcast: 172.25.1.127
HostMin: 172.25.1.65
HostMax: 172.25.1.126
Hosts/Net: 62

and the gateway will be (broadcast-1) = 172.25.1.126

To find out what the default gateway is:
cat /etc/sysconfig/network

initialization scripts in /etc/sysconfig/network-scripts/ifcfg-*



https://en.wikipedia.org/wiki/Broadcast_address